1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 | CLS TYPE rodnya f AS STRING * 20 n AS STRING * 10 p AS STRING * 5 v AS INTEGER k AS STRING * 20 d AS STRING * 10 END TYPE DIM a( 5 ) AS rodnya DATA "Ivanov","Ivan","m", 40 ,"brat"," 20.04.70 " DATA "Petrov","petr","m", 23 ,"kuzin"," 14.03.87 " DATA "Suvorov","Semen","m", 43 ,"otec"," 25.12.67 " DATA "Kuznecova","Lena","zh", 25 ,"zhena"," 28.12.84 " DATA "Soboleva","Olga","zh", 32 ,"sestra"," 15.12.78 " FOR i = 1 TO 5 READ a(i).f READ a(i).n READ a(i).p READ a(i).v READ a(i).k READ a(i).d NEXT i PRINT "Familiya"; TAB( 21 ); "Imya"; " "; "Pol"; PRINT " vozr"; " kem prihoditsya"; " data rozhden" PRINT FOR i = 1 TO 5 PRINT a(i).f; a(i).n; a(i).p; a(i).v; " "; a(i).k; a(i).d NEXT i FOR i = 1 TO 5 FOR j = i + 1 TO 5 FOR l = 1 TO LEN(a(i).f) b1$ = MID$(a(i).f, l, 1 ): b2$ = MID$(a(j).f, l, 1 ) IF b1$ > b2$ THEN SWAP a(i), a(j) EXIT FOR ELSEIF b1$ < b2$ THEN EXIT FOR END IF NEXT l NEXT j NEXT i PRINT PRINT "Familii rodstvennikov v alfavitnom poryadke" PRINT FOR i = 1 TO 5 PRINT a(i).f NEXT i min = a( 1 ).v: mini = 1 FOR i = 2 TO 5 IF a(i).v < min THEN min = a(i).v: imin = i NEXT i PRINT PRINT "Samiy molodoy rodstvennik "; a(imin).f; " " |
Тестирование выполнено в программе QB64 ( Скачать )